Question 51995PhysicsWAEC

Calculate the energy carried by an X-ray of wavelength 6.0 x 10 -10 m (Planck’s constant = 6.6 x 10−34^{-34} Js, velocity of light = 3.0 x 108^{8} ms -−17^{-17}J)

A

3.3 x 10 −12^{-12} J

B

3.3 x 10−16^{-16} J

C

1.1 X 10−16^{-16}J

D

3.3 x 10−24^{-24} J

Step-by-Step Explanation

Energy of a photon can be calculated using the formula E=hcλE = \frac{hc}{\lambda}, where hh is Planck's constant, cc is the speed of light, and λ\lambda is the wavelength. Substituting the given values, h=6.6×10−34h = 6.6 \times 10^{-34} Js, c=3.0×108c = 3.0 \times 10^{8} m/s, and λ=6.0×10−10\lambda = 6.0 \times 10^{-10} m, results in an energy value of approximately 3.3×10−163.3 \times 10^{-16} J. This calculation demonstrates the inverse relationship between wavelength and energy, where shorter wavelengths correspond to higher energy photons.

Comments (0)