Question 252017PhysicsWAEC

A converging lens of focal length 10cm forms an erect image three times the size of a real object. Calculate the distance between the object and the image?

A

6.6cm

B

11.1cm

C

13.3cm

D

20.0cm

Step-by-Step Explanation

For a converging lens, the magnification (m) is given by the ratio of the image distance (v) to the object distance (u), where m = v/u. In this case, since the image is erect and three times the size of the object, m = 3, leading to the relationship v = 3u. Using the lens formula (1/f = 1/v - 1/u) with the focal length of 10 cm allows for the calculation of the distances, resulting in a total distance between the object and the image of 13.3 cm.

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