Question 252017PhysicsWAEC
A converging lens of focal length 10cm forms an erect image three times the size of a real object. Calculate the distance between the object and the image?
A
6.6cm
B
11.1cm
C
13.3cm
D
20.0cm
Step-by-Step Explanation
For a converging lens, the magnification (m) is given by the ratio of the image distance (v) to the object distance (u), where m = v/u. In this case, since the image is erect and three times the size of the object, m = 3, leading to the relationship v = 3u. Using the lens formula (1/f = 1/v - 1/u) with the focal length of 10 cm allows for the calculation of the distances, resulting in a total distance between the object and the image of 13.3 cm.