Question 282020PhysicsWAEC

The magnitude of the force experienced by a charge of 1.6 x 10 -8 C in a uniform electric field of intensity 5 x 10 3 NC is

A

3.2 x 10 -14 N

B

8.0 x 10 -3 N

C

8.0 x 10 3 N

D

3.1 x 10 13 N

Step-by-Step Explanation

The force experienced by a charge in an electric field can be calculated using the formula F = qE, where F is the force, q is the charge, and E is the electric field intensity. Substituting the given values, F = (1.6 x 10^-8 C)(5 x 10^3 N/C) results in a force of 8.0 x 10^-3 N. This demonstrates how the interaction between charge and electric field intensity determines the resultant force.

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