Question 32006PhysicsWAEC

How long will it take to heat 3 kg of water from 28°C to 88°C in an electric kettle taking 6A from a 220V supply? [specific heat capacity of water = 4180 jkg -1 k -1 ]

A

120 s

B

570 s

C

600 s

D

836 s

Step-by-Step Explanation

To calculate the time required to heat the water, first determine the energy needed using the formula Q=mcΔTQ = mc\Delta T, where mm is the mass of the water, cc is the specific heat capacity, and ΔT\Delta T is the change in temperature. The power supplied by the kettle can be calculated using P=VIP = VI, where VV is the voltage and II is the current; this gives the energy per second. Finally, divide the total energy required by the power to find the time taken to heat the water.

Comments (0)