Question 322018MathematicsJAMB

If (251−x×5x+2)÷(125)x=625−1(25^{1-x} \times 5^{x+2}) \div (\frac{1}{25})^x = 625^{-1}.

A

x = -4

B

x = 2

C

x = -2

D

x = 4

Step-by-Step Explanation

To solve the equation, first express all terms with a common base, which is 5: 25=5225 = 5^2 and 625=54625 = 5^4. Rewriting the equation gives 52(1−x)×5x+2÷5−2x=5−45^{2(1-x)} \times 5^{x+2} \div 5^{-2x} = 5^{-4}, simplifying to 52−2x+x+2+2x=5−45^{2 - 2x + x + 2 + 2x} = 5^{-4}. Setting the exponents equal leads to the equation 2+2=−42 + 2 = -4, which simplifies to x=−4x = -4.

Comments (0)